a) x^3 + 4x^2 - 29x + 24
b) x5 + x + 1
c) ( x+1 ) * ( x+3 ) * ( x+5 ) * ( x+7 ) + 15
d) ( x-1 ) * ( x-3 ) * ( x-5 ) * ( x-7 )* x - 20
e) x8 + x + 1
phân tích đa thức thành nhân tử
a, x3 +4x2 -29x +24
b, x3 +6x2 +11x +6
c, (x + 1)(x - 3)(x + 7) +15
d, (x +1)(x + 3)(x + 5)(x +7) - 20
e, (x +1)(x + 2)(x + 3)(x + 4) -24
Bài toán 3 : Tìm x, biết.
a. 2(x – 5) – 3(x + 7) = 14 b. 5(x – 6) – 2(x + 3) = 12
c. 3(x – 4) – (8 – x) = 12 d. -7(3x – 5) + 2(7x – 14) = 28
e. 5(3 – 2x) + 5(x – 4) = 6 – 4x f. -5(2 – x) + 4(x – 3) = 10x – 15
g. 2(4x – 8) – 7(3 + x) = |-4|(3 – 2) h. 8(x – |-7|) – 6(x – 2) = |-8|.6 – 50
k. -7(5 – x) – 2(x – 10) = 15 l. 4(x – 1) – 3(x – 2) = -|-5|
m. -4(x + 1) + 89x – 3) = 24 n. 5(x – 30 – 2(x + 6) = 9
o. -3(x – 5) + 6(x + 2) = 9 p. 7(x – 9) – 5(6 – x) = – 6 + 11x
q. 10(x – 7) – 8(x + 5) = 6.(-5) + 24
nhiều quá :((
\(a,2\left(x-5\right)-3\left(x+7\right)=14\)
\(2x-10-3x-21=14\)
\(-x-31=14\)
\(-x=45\)
\(x=45\)
\(b,5\left(x-6\right)-2\left(x+3\right)=12\)
\(5x-30-2x-6=12\)
\(3x-36==12\)
\(3x=48\)
\(x=16\)
\(c,3\left(x-4\right)-\left(8-x\right)=12\)
\(3x-12-8+x=0\)
\(4x-20=0\)
\(4x=20\)
\(x=5\)
Cố nốt nha bn !
cảm ơn, bn nha:)))
mà hình như bạn TOP 3 trả lời câu hỏi pải ko nhỉ???
d, \(-7\left(3x-5\right)+2\left(7x-14\right)=28\)
\(\Leftrightarrow-21x+35+14x-28=28\Leftrightarrow-7x=21\Leftrightarrow x=-3\)
e, \(5\left(3-2x\right)+5\left(x-4\right)=6-4x\)
\(\Leftrightarrow15-6x+5x-20=6-4x\Leftrightarrow-5-x=6-4x\)
\(\Leftrightarrow-11+3x=0\Leftrightarrow x=\frac{11}{3}\)
f, \(-5\left(2-x\right)+4\left(x-3\right)=10x-15\)
\(\Leftrightarrow-10+5x+4x-12=10x-15\Leftrightarrow-22+9x=10x-15\)
\(\Leftrightarrow-7-x=0\Leftrightarrow x=-7\)
1 : Tìm x , biết :
a, 4x - 5 . ( -3 + x ) = 7
b, -4 . ( x + 1 ) + 8 . ( x - 3 ) = 24
c, 7. ( 5 - x ) + 5 . ( x - 2 ) = 15
d, 4 . ( x - 1 ) - 3 . ( x - 2 ) = -5
Phân tích đa thức thành nhân tử ( đặt biến phụ):
a) (x^2+x)^2-14(x^2+x) + 24
b) (x^2+x)^2 + 4x^2+4x-12
c) x^4 + 2x^3+ 5x^2+4x-12
d) (x+1)(x+2)(x+3)(x+4)+1
e) (x+1)(x+3)(x+5)(x+7)+15
f) (x+1)(x+2)(x+3)(x+4)-24
a. -3(x-5)+6(x-2)=9
b. 4x-5(-3+x)=7
c. 5(x-7)+10(3-x)=20
d. -4(x+1)+8(x-3)=24
a/ \(-3\left(x-5\right)+6\left(x-2\right)=9\)
\(\Rightarrow-3x-\left(-3.5\right)+6x-\left(6.2\right)=9\)
\(\Rightarrow-3x+15+6x-12=9\)
\(\Rightarrow-3x+6x=9+12-15\)
\(\Rightarrow3x=6\)
\(\Rightarrow x=2\)
b/ \(4x-5\left(-3+x\right)=7\)
\(\Rightarrow4x-5.\left(-3\right)-5x=7\)
\(\Rightarrow4x+15-5x=7\)
\(\Rightarrow4x-5x=7-15\)
\(\Rightarrow-1x=-8\)
\(\Rightarrow x=8\)
c/ \(5\left(x-7\right)+10\left(3-x\right)=20\)
\(\Rightarrow5x-5.7+10.3-10x=20\)
\(\Rightarrow5x-35+30-10=20\)
\(\Rightarrow5x-10x=20-30+35\)
\(\Rightarrow-5x=25\)
\(\Rightarrow x=-5\)
d/ \(-4\left(x+1\right)+8\left(x-3\right)=24\)
\(\Rightarrow-4x-4.1+8x-8.6=3=24\)
\(\Rightarrow-4x-4+8x-24=24\)
\(\Rightarrow-4x+8x=24+24+4\)
\(\Rightarrow4x=52\)
\(\Rightarrow x=13\)
a) -3(x-5)+6(x-2)=9
<=>-3x+15+6x-12-9=0
<=>3x=6
<=>x=2
Vậy x=2
b)4x-5(-3+x)=7
<=>4x+15-5x=7
<=>-x=-8
<=>x=8
Vậy x=8
Giải các phương trình sau:
A) 1/x-2+3=3-x/x-2
B)8-x/x-7-8=-26/x-7
C)1/x-2+1/x-3=2/x-1
D)X^3-1/X=(x-2)(x+2)+11/x
E)x+5/x-5-x-5/x+5=20/x^2-25
F)x+7/x-3+4x-2/x-5=5
a: \(\dfrac{1}{x-2}+3=\dfrac{3-x}{x-2}\)
=>1+3x-6=3-x
=>3x-5=3-x
=>4x=8
hay x=2(loại)
b: \(\Leftrightarrow8-x-8\left(x-7\right)=-26\)
=>8-x-8x+56=-26
=>-9x+64=-26
=>-9x=-90
hay x=10(nhận)
c: \(\dfrac{1}{x-2}+\dfrac{1}{x-3}=\dfrac{2}{x-1}\)
\(\Leftrightarrow\dfrac{x-3+x-2}{\left(x-2\right)\left(x-3\right)}=\dfrac{2}{x-1}\)
\(\Leftrightarrow\left(x-1\right)\left(2x-5\right)=2\left(x^2-5x+6\right)\)
\(\Leftrightarrow2x^2-5x-2x+5=2x^2-10x+12\)
=>-7x+10x=12-5
=>3x=7
hay x=7/3(nhận)
bài 12: phân tích đa thức sau thànnh nhân tử (đặt biến phụ)
b, (x2+x)2+4x2+4x-12
c, x4+2x3+5x2+4x-12
d, (x+1)(x+2)(x+3)(x+4)+1
e, (x+1)(x+3)(x+5)(x+7)+15
f, (x+1)(x+2)(x+3)(x+4)-24
bài 13: (giống đề bài trên)
a, (x2+4x+8)2+3x(x2+4x+8)+2x2
b, (x2+x+1)(x2+x+2)-12
c, (x2+8x+7)(x2+8x+15)+15
d, (x+2)(x+3)(x+4)(x+5)-24
bÀI LÀM
a) x4+x3+2x2+x+1=(x4+x3+x2)+(x2+x+1)=x2(x2+x+1)+(x2+x+1)=(x2+x+1)(x2+1)
b)a3+b3+c3-3abc=a3+3ab(a+b)+b3+c3 -(3ab(a+b)+3abc)=(a+b)3+c3-3ab(a+b+c)
=(a+b+c)((a+b)2-(a+b)c+c2)-3ab(a+b+c)=(a+b+c)(a2+2ab+b2-ac-ab+c2-3ab)=(a+b+c)(a2+b2+c2-ab-ac-bc)
c)Đặt x-y=a;y-z=b;z-x=c
a+b+c=x-y-z+z-x=o
đưa về như bài b
d)nhóm 2 hạng tử đầu lại và 2hangj tử sau lại để 2 hạng tử sau ở trong ngoặc sau đó áp dụng hằng đẳng thức dề tính sau đó dặt nhân tử chung
e)x2(y-z)+y2(z-x)+z2(x-y)=x2(y-z)-y2((y-z)+(x-y))+z2(x-y)
=x2(y-z)-y2(y-z)-y2(x-y)+z2(x-y)=(y-z)(x2-y2)-(x-y)(y2-z2)=(y-z)(x2-2y2+xy+xz+yz)
1. Giải các phương trình:
a) (x²+x+1)(x²+x+2)=12
b) (x²+x+6)(x²+x+3)=6
c) (x²+5x)²-2(x²+5x)-24=0
d) (x²-4x)²+2(x²-4x)-8=0
e) (2-x²)²+3(2-x²)+2=0
f) (x²-6x)²-2(x-3)²=81
g) (x²+2x)²-(x+1)²=55
h) x(x+1)(x-1)(x+2)=24
i) (x-4)(x-5)(x-6)(x-7)=1680
j) (x+1)(x+2)(x+5)(x-2)=-20
k) (x+1)(x+2)(x+3)(x+4)=3
l) (x-2)(x-4)(x+6)(x+8)=-36
m) (x-1)(x-3)(x+5)(x+7)=297
n) (x+1)(x+3)(x+5)(x+7)=9
o) (8x+7)²(4x+3)(x+1)=4,5
1. TÌm x:
a)4x^2-2x+3-4x.(x-5)=7x-3
b)-3x.(x-5)+5.(x-1)+3x^2=4x
c)7x.(x-2)-5.(x-1)=21x^2-14x^2+3
d)3.(5x-1)-x.(x-2)+x^2-13x=7
e) 1/5x.(10x-15)-2x.(x-5)=12
a) 4x2 - 2x + 3 - 4x.(x - 5) = 7x - 3
--> 4x2 - 2x + 3 - 4x2 + 20x = 7x - 3
--> 4x2 - 2x - 4x2 + 20x - 7x = -3 - 3
--> 11x = -6
--> x = \(\frac{-6}{11}\)
b) -3x.(x - 5) + 5.(x - 1) + 3x2 = 4x
--> -3x2 + 15x + 5x - 5 + 3x2 = 4x
--> -3x2 + 15x + 5x + 3x2 - 4x = 5
--> 16x = 5
--> x = \(\frac{5}{16}\)
c) 7x.(x - 2) - 5.(x - 1) = 21x2 - 14x2 + 3
--> 7x2 - 14x - 5x + 5 = 7x2 + 3
--> 7x2 - 14x - 5x - 7x2 = -5 + 3
--> -19x = -2
--> x = \(\frac{2}{19}\)
d) 3.(5x - 1) - x.(x - 2) + x2 - 13x = 7
--> 15x - 3 - x2 + 2x + x2 - 13x = 7
--> 15x - x2 + 2x + x2 - 13x = 3 + 7
--> 4x = 10
--> x = \(\frac{5}{2}\)
e) \(\frac{1}{5}\)x.(10x - 15) - 2x.(x - 5) = 12
--> 2x2 - 3x - 2x2 + 10x = 12
--> 7x = 12
--> x = \(\frac{12}{7}\)
~ Học tốt ~